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" content = urlopen(req, timeout=1, context=SSLContext())\n",
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" \\min \\mspace{-6mu}&\\mspace{-6mu} \\mspace{-6mu}&\\mspace{-6mu} 148 y_{1} \\mspace{-6mu}&\\mspace{-6mu} + \\mspace{-6mu}&\\mspace{-6mu} 23 y_{2} \\mspace{-6mu}&\\mspace{-6mu} + \\mspace{-6mu}&\\mspace{-6mu} 28 y_{3} \\mspace{-6mu}&\\mspace{-6mu} \\mspace{-6mu}&\\mspace{-6mu} \\\\\n",
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"\\end{array} \\\\\n",
"y_{1}, y_{2}, y_{3} \\geq 0\n",
"\\end{array}$$"
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"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\frac{7}{4},\\,0,\\,\\frac{11}{2}\\right)$$"
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"(7/4, 0, 11/2)"
]
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""
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"text/latex": [
"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\begin{array}{r|rrrrrr|r}\n",
"{Basic} & {x}_{1} & {x}_{2} & {x}_{3} & {\\color{green}{s}}_{1} & {\\color{green}{s}}_{2} & {\\color{green}{s}}_{3} & {b} \\\\\n",
"\\hline\n",
" {\\color{green}{s}}_{1} & 4 & 6 & 2 & 1 & 0 & 0 & 148 \\\\\n",
"{\\color{green}{s}}_{2} & 1 & \\frac{1}{2} & 1 & 0 & 1 & 0 & 23 \\\\\n",
"{\\color{green}{s}}_{3} & 1 & 1 & 1 & 0 & 0 & 1 & 28 \\\\\n",
"\\hline\n",
" {Z_{ind}} & 8 & 16 & 9 & 0 & 0 & 0 & 0\n",
"\\end{array}\\right)$$"
],
"text/plain": [
"[ B| x1 x2 x3 s1 s2 s3|rhs]\n",
"[---+-----------------------+---]\n",
"[ s1| 4 6 2 1 0 0|148]\n",
"[ s2| 1 1/2 1 0 1 0| 23]\n",
"[ s3| 1 1 1 0 0 1| 28]\n",
"[---+-----------------------+---]\n",
"[ Z| 8 16 9 0 0 0| 0]"
]
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{
"name": "stdout",
"output_type": "stream",
"text": [
"cambio( 1 , 2 )\n"
]
},
{
"data": {
"text/html": [
""
],
"text/latex": [
"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\begin{array}{r|rrrrrr|r}\n",
"{Basic} & {x}_{1} & {x}_{2} & {x}_{3} & {\\color{green}{s}}_{1} & {\\color{green}{s}}_{2} & {\\color{green}{s}}_{3} & {b} \\\\\n",
"\\hline\n",
" {x}_{2} & \\frac{2}{3} & 1 & \\frac{1}{3} & \\frac{1}{6} & 0 & 0 & \\frac{74}{3} \\\\\n",
"{\\color{green}{s}}_{2} & \\frac{2}{3} & 0 & \\frac{5}{6} & -\\frac{1}{12} & 1 & 0 & \\frac{32}{3} \\\\\n",
"{\\color{green}{s}}_{3} & \\frac{1}{3} & 0 & \\frac{2}{3} & -\\frac{1}{6} & 0 & 1 & \\frac{10}{3} \\\\\n",
"\\hline\n",
" {Z_{ind}} & -\\frac{8}{3} & 0 & \\frac{11}{3} & -\\frac{8}{3} & 0 & 0 & \\frac{1184}{3}\n",
"\\end{array}\\right)$$"
],
"text/plain": [
"[ B| x1 x2 x3 s1 s2 s3| rhs]\n",
"[------+-----------------------------------------+------]\n",
"[ x2| 2/3 1 1/3 1/6 0 0| 74/3]\n",
"[ s2| 2/3 0 5/6 -1/12 1 0| 32/3]\n",
"[ s3| 1/3 0 2/3 -1/6 0 1| 10/3]\n",
"[------+-----------------------------------------+------]\n",
"[ Z| -8/3 0 11/3 -8/3 0 0|1184/3]"
]
},
"metadata": {},
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"name": "stdout",
"output_type": "stream",
"text": [
"cambio( 3 , 3 )\n"
]
},
{
"data": {
"text/html": [
""
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"text/latex": [
"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\begin{array}{r|rrrrrr|r}\n",
"{Basic} & {x}_{1} & {x}_{2} & {x}_{3} & {\\color{green}{s}}_{1} & {\\color{green}{s}}_{2} & {\\color{green}{s}}_{3} & {b} \\\\\n",
"\\hline\n",
" {x}_{2} & \\frac{1}{2} & 1 & 0 & \\frac{1}{4} & 0 & -\\frac{1}{2} & 23 \\\\\n",
"{\\color{green}{s}}_{2} & \\frac{1}{4} & 0 & 0 & \\frac{1}{8} & 1 & -\\frac{5}{4} & \\frac{13}{2} \\\\\n",
"{x}_{3} & \\frac{1}{2} & 0 & 1 & -\\frac{1}{4} & 0 & \\frac{3}{2} & 5 \\\\\n",
"\\hline\n",
" {Z_{ind}} & -\\frac{9}{2} & 0 & 0 & -\\frac{7}{4} & 0 & -\\frac{11}{2} & 413\n",
"\\end{array}\\right)$$"
],
"text/plain": [
"[ B| x1 x2 x3 s1 s2 s3| rhs]\n",
"[-----+-----------------------------------+-----]\n",
"[ x2| 1/2 1 0 1/4 0 -1/2| 23]\n",
"[ s2| 1/4 0 0 1/8 1 -5/4| 13/2]\n",
"[ x3| 1/2 0 1 -1/4 0 3/2| 5]\n",
"[-----+-----------------------------------+-----]\n",
"[ Z| -9/2 0 0 -7/4 0 -11/2| 413]"
]
},
"metadata": {},
"output_type": "display_data"
},
{
"name": "stdout",
"output_type": "stream",
"text": [
"El problema es óptimo\n"
]
}
],
"source": [
"tipo='max' # max o min\n",
"\n",
"n=3 # número de variables x's\n",
"m=3 # número de restricciones (distintas de las de signo)\n",
"\n",
"cMP=matrix(QQ,1,m,[1.5,2,4] ) # coste de las materias primas\n",
"\n",
"\n",
"A=matrix(QQ,m,n,[ # coeficientes de las variables x's\n",
"[4, 6, 2],\n",
"[1, 0.5, 1],\n",
"[1, 1, 1]\n",
"])\n",
"\n",
"cf=cMP*A # coste de cada unidad de producto fabricada\n",
"\n",
"\n",
"venta=matrix(QQ,1,n,[20,30,18]) # precio de venta\n",
"\n",
"c=venta-cf # vector de costos (beneficio en este caso)\n",
"\n",
"\n",
"b=matrix(QQ,m,1,[148,23,28]) # vector de la derecha\n",
"\n",
"\n",
"############### VARIABLES DE HOLGURA ################\n",
"\n",
"\n",
"h=matrix(ZZ,1,m,[1,1,1]) # variables de holgura: \n",
" # Pon 1 si va sumando, \n",
" # -1 si va restando y \n",
" # 0 si no hay variable de holgura.\n",
"\n",
"#######################################################\n",
"\n",
"load('https://sage.unex.es/501708/simplex2023Auto.sage')\n",
"\n",
"#load('https://matematicas.unex.es/~jaoyola/SAGE/simplex2023Auto.sage')\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"\n",
"## Calculando el 'shadow price' de la línea 1 (Harina)\n",
"Suponemos que $\\lambda$ es el parámetro."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": []
},
{
"cell_type": "code",
"execution_count": 11,
"metadata": {},
"outputs": [],
"source": [
"#b1p=matrix(QQ,m,1,[0,1,0,0]); param1b(b1p)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Para $\\lambda=1$, este cuadro es óptimo. Por tanto, 7/4 sería el precio máximo que pagaríamos por un por un kg adicional de harina. "
]
},
{
"cell_type": "code",
"execution_count": 12,
"metadata": {},
"outputs": [],
"source": [
"#cambio(3,4)"
]
},
{
"cell_type": "code",
"execution_count": 13,
"metadata": {},
"outputs": [],
"source": [
"#cocientesD(3)"
]
},
{
"cell_type": "code",
"execution_count": 14,
"metadata": {},
"outputs": [],
"source": [
"#b1p=matrix(QQ,m,1,[0,0,1,0]); param1b(b1p)"
]
},
{
"cell_type": "code",
"execution_count": 15,
"metadata": {},
"outputs": [],
"source": [
"#cocientesD(2)"
]
},
{
"cell_type": "code",
"execution_count": 16,
"metadata": {},
"outputs": [],
"source": [
"#cambio(2,6)"
]
},
{
"cell_type": "code",
"execution_count": 17,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"24.2000000000000"
]
},
"execution_count": 17,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"2096/5. - 395"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Calculando los 'shadow prices' de dos líneas simultáneamente:"
]
},
{
"cell_type": "code",
"execution_count": 18,
"metadata": {},
"outputs": [
{
"data": {
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""
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"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\begin{array}{r|rrrrrrr|rrr}\n",
"{Basic} & {x}_{1} & {x}_{2} & {x}_{3} & {\\color{green}{s}}_{1} & {\\color{green}{s}}_{2} & {\\color{green}{s}}_{3} & {\\color{green}{s}}_{4} & {b} & {b_1} & {b_2} \\\\\n",
"\\hline\n",
" {x}_{2} & 0 & 1 & 0 & \\frac{1}{4} & 0 & -\\frac{1}{2} & \\frac{1}{2} & 21 & \\frac{1}{4} & 0 \\\\\n",
"{\\color{green}{s}}_{2} & 0 & 0 & 0 & \\frac{1}{8} & 1 & -\\frac{5}{4} & \\frac{1}{4} & \\frac{11}{2} & \\frac{1}{8} & 1 \\\\\n",
"{x}_{3} & 0 & 0 & 1 & -\\frac{1}{4} & 0 & \\frac{3}{2} & \\frac{1}{2} & 3 & -\\frac{1}{4} & 0 \\\\\n",
"{x}_{1} & 1 & 0 & 0 & 0 & 0 & 0 & -1 & 4 & 0 & 0 \\\\\n",
"\\hline\n",
" {Z_{ind}} & 0 & 0 & 0 & -\\frac{7}{4} & 0 & -\\frac{11}{2} & -\\frac{9}{2} & 395 & \\frac{7}{4} & 0\n",
"\\end{array}\\right)$$"
],
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"[ B| x1 x2 x3 s1 s2 s3 s4| rhs rhs1 rhs2]\n",
"[-----+-----------------------------------------+-----------------]\n",
"[ x2| 0 1 0 1/4 0 -1/2 1/2| 21 1/4 0]\n",
"[ s2| 0 0 0 1/8 1 -5/4 1/4| 11/2 1/8 1]\n",
"[ x3| 0 0 1 -1/4 0 3/2 1/2| 3 -1/4 0]\n",
"[ x1| 1 0 0 0 0 0 -1| 4 0 0]\n",
"[-----+-----------------------------------------+-----------------]\n",
"[ Z| 0 0 0 -7/4 0 -11/2 -9/2| 395 7/4 0]"
]
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],
"source": [
"b1p=matrix(QQ,m,1,[1,0,0,0]); b2p=matrix(QQ,m,1,[0,1,0,0]); param2b(b1p,b2p)"
]
},
{
"cell_type": "code",
"execution_count": 19,
"metadata": {},
"outputs": [
{
"data": {
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"$$\\newcommand{\\Bold}[1]{\\mathbf{#1}}\\left(\\begin{array}{r|rrrrrrr|rrrr}\n",
"{Basic} & {x}_{1} & {x}_{2} & {x}_{3} & {\\color{green}{s}}_{1} & {\\color{green}{s}}_{2} & {\\color{green}{s}}_{3} & {\\color{green}{s}}_{4} & {b} & {b_1} & {b_2} & {b_1} \\\\\n",
"\\hline\n",
" {x}_{2} & 0 & 1 & 0 & \\frac{1}{4} & 0 & -\\frac{1}{2} & \\frac{1}{2} & 21 & \\frac{1}{4} & 0 & -\\frac{1}{2} \\\\\n",
"{\\color{green}{s}}_{2} & 0 & 0 & 0 & \\frac{1}{8} & 1 & -\\frac{5}{4} & \\frac{1}{4} & \\frac{11}{2} & \\frac{1}{8} & 1 & -\\frac{5}{4} \\\\\n",
"{x}_{3} & 0 & 0 & 1 & -\\frac{1}{4} & 0 & \\frac{3}{2} & \\frac{1}{2} & 3 & -\\frac{1}{4} & 0 & \\frac{3}{2} \\\\\n",
"{x}_{1} & 1 & 0 & 0 & 0 & 0 & 0 & -1 & 4 & 0 & 0 & 0 \\\\\n",
"\\hline\n",
" {Z_{ind}} & 0 & 0 & 0 & -\\frac{7}{4} & 0 & -\\frac{11}{2} & -\\frac{9}{2} & 395 & \\frac{7}{4} & 0 & \\frac{11}{2}\n",
"\\end{array}\\right)$$"
],
"text/plain": [
"[ B| x1 x2 x3 s1 s2 s3 s4| rhs rhs1 rhs2 rhs1]\n",
"[-----+-----------------------------------------+-----------------------]\n",
"[ x2| 0 1 0 1/4 0 -1/2 1/2| 21 1/4 0 -1/2]\n",
"[ s2| 0 0 0 1/8 1 -5/4 1/4| 11/2 1/8 1 -5/4]\n",
"[ x3| 0 0 1 -1/4 0 3/2 1/2| 3 -1/4 0 3/2]\n",
"[ x1| 1 0 0 0 0 0 -1| 4 0 0 0]\n",
"[-----+-----------------------------------------+-----------------------]\n",
"[ Z| 0 0 0 -7/4 0 -11/2 -9/2| 395 7/4 0 11/2]"
]
},
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}
],
"source": [
"b3p=matrix(QQ,m,1,[0,0,1,0]);param1b(b3p)"
]
}
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